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The Riemann zeta function is the function of one complex variable $s$ defined by the series $\zeta(s) = \sum_{n \geq 1} \frac{1}{n^s}$ when $\operatorname{Re}(s)>1$. It admits a meromorphic continuation to $\mathbb{C}$ with only a simple pole at $1$. This function satisfies a functional equation relating the values at $s$ and $1-s$. This is the most simple example of an $L$-function and a central object of number theory.

19 votes
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Are there any papers about this observation of the distribution of the zeros of the zeta fun...

This is called Landau's formula. More precisely, if we extend the von Mangoldt function $\Lambda(n)$ to the function $\Lambda:\mathbb R_+\to \mathbb R$ by $\Lambda(x)=0$ for non-integer $x$, then $$ \ …
Alexander Kalmynin's user avatar
14 votes

Non trivial zeros of Riemann zeta function

Authors of the paper you linked actually define $f(z)$ differently. They have $$ f(z)=\left(\frac{1}{1-z}-1\right)\zeta\left(\frac{1}{1-z}\right), $$ so your $f(z)$ is their $f(-z^2)$ and every $\alph …
Alexander Kalmynin's user avatar
4 votes
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Robin's inequality and the zeros of the Riemann zeta function

It is well-known that the Riemann hypothesis implies $$ \theta(x)=x+O(\sqrt{x}\ln^2 x). $$ Therefore, under the Riemann hypothesis we have $$ \ln\theta(x)=\ln x+O\left(\frac{\ln^2 x}{\sqrt{x}}\right). …
Alexander Kalmynin's user avatar
2 votes

On the nearest integer to $\zeta^{(k)}(1-1/B),B \ge 2$

Both conjectures are false. Suppose your conjectured identity holds for all $k\geq 1$ and some $B\geq 2$. It is known that $$ f(s)=\zeta(s)-\frac{1}{s-1} $$ is an entire function. Your identity for fi …
Alexander Kalmynin's user avatar