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Complex geometry is the study of complex manifolds, complex algebraic varieties, complex analytic spaces, and, by extension, of almost complex structures. It is a part of differential geometry, algebraic geometry and analytic geometry.

22 votes

flatness in complex analytic geometry

Mohammad, flatness is not simple, so you are not going to get a simple overall definition. On the other hand, in the example you mention in your comment, there is a simple criterion: Let $f:X\to …
Sándor Kovács's user avatar
14 votes
Accepted

Hodge theory on complex spaces

Let me add to Donu's mentioning Du Bois's Hodge decomposition. First of all, many feel that part of the credit is due to Deligne as Du Bois built heavily on his ideas. Then again that is probably true …
Sándor Kovács's user avatar
14 votes
Accepted

Generalisations of Riemann-Roch for surfaces

If $X$ is proper with rational singularities (and quotient and A-D-E (=Du Val) singularities are rational), then you can do most cohomology computations on a resolution. Let $\pi:Y\to X$ be a resoluti …
Sándor Kovács's user avatar
13 votes

Trying to Understand Lefschetz Pencils

Note: I am using the word "smooth" in the sense of algebraic geometry. For a differential geometer it would be "submersion". If by "smooth" you mean $C^\infty$, then every map is smooth here (so there …
Sándor Kovács's user avatar
11 votes

Intuition behind the Kodaira Vanishing Theorem?

Here are some thoughts. For simplicity I will call a line bundle positive if it admits a metric as you described. According to Serre's vanishing theorem for any (fixed) coherent sheaf $F$, the sheaf …
Sándor Kovács's user avatar
10 votes
Accepted

Additivity of Kodaira dimension for a nice fibration

There is another inequality which says the following: Easy addition (Using the same notation): $$ \kappa(X)\leqslant \kappa(X_y) + \dim Y $$ Consequently, if $Y$ is of general type, i.e., $ …
Sándor Kovács's user avatar
9 votes
Accepted

How many points determine a line?

As Artie points out, you can't do this with actual lines, but the next best thing is to ask the question with rational curves of minimal degree. If you have lines those will automatically be of minima …
Sándor Kovács's user avatar
9 votes
Accepted

how to prove the following fact in sheaf cohomology ?

$\dim\mathrm{Supp}\\, \mathfrak F=0$ implies that $\mathfrak F\otimes \mathscr O_X(L)\simeq \mathfrak F$ and hence its cohomology is independent of $L$.
Sándor Kovács's user avatar
9 votes
Accepted

Surgery in complex geometry

There is an operation in algebraic geometry, called a flip, which is a (kind of a special) surgery, so one could say that you hear about it, but under a different name. You can see the definition of a …
Sándor Kovács's user avatar
9 votes
Accepted

Morphism between projective varieties

Here is an attempt to prove Angelo's comment (it seems too simple to use a reference for it): $X,Y$ defined over $S$. If they are both proper over $S$, then so is $f$ by Hartshorne, II.4.8(e). In par …
Sándor Kovács's user avatar
9 votes
Accepted

Is the set of surfaces over Spec Z with ample canonical sheaf empty

I don't think the answer to the first question is known. Will has already pointed out the trivial answer to the second question. However this is not the right question. I mean this is kind of trivia …
Sándor Kovács's user avatar
8 votes
Accepted

Uniformity of ampleness

Remark: If $p=q$, then one can just work with $E_p$ instead of $2E_p$ and then at the end take $2k_0$ instead of $k_0$, so we may assume that $p\neq q$ and in particular that the exceptional diviso …
Sándor Kovács's user avatar
8 votes

in the analytic category, finite morphisms are open maps?

Open Mapping Theorem [Grauert-Remmert: Coherent analytic sheaves, p.107] Let $X,Y$ be pure $d$-dimensional complex spaces and assume that $Y$ is locally irreducible. Then any holomorphic map $f:X\to Y …
Sándor Kovács's user avatar
8 votes
Accepted

Basepoints in the canonical system of algebraic surfaces

In the general case when $n=\dim X$ is arbitrary Kollár proves an analogue for minimal varieties of general type, although the bound is much worse than in the surface case. In the situation at hand it …
Sándor Kovács's user avatar
7 votes
Accepted

There are only finitely many varieties up to deformation

I believe the two things you are relating: The finiteness of the number of deformation types number of components of the moduli space of polarized varieties are essentially equivalent problems. …
Sándor Kovács's user avatar

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