Skip to main content
2 of 2
deleted 183 characters in body; edited title
Akira
  • 825
  • 2
  • 9
  • 16

Does $f(t) \le \int_0^t (t-s)^{-\frac{1}{2}} [f(s) + |f(s)|^{\beta}] \, \mathrm d s$ imply $f=0$?

Let $\beta \in (0, 1)$. We assume $f : [0, 1] \to [0, \infty)$ is a measurable and bounded function such that $$ f(t) \le \int_0^t (t-s)^{-\frac{1}{2}} [f(s) + |f(s)|^{\beta}] \, \mathrm d s, \quad \forall t \in [0, 1]. $$

I would like to ask if $f=0$?

Thank you so much for your elaboration!

Akira
  • 825
  • 2
  • 9
  • 16