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Akira
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A tight Grönwall Does $f(t) \le \int_0^t (t-type upper bounds)^{-\frac{1}{2}} [f(s) + |f(s)|^{\beta}] \, \mathrm d s$ imply $f=0$?

Let $\alpha \in (0, \infty)$ and $\beta \in (0, 1]$$\beta \in (0, 1)$. We assume $f : [0, 1] \to [0, \infty)$ is a measurable and bounded function such that $$ f(t) \le \alpha + \int_0^t (t-s)^{-\frac{1}{2}} [f(s) + |f(s)|^{\beta}] \, \mathrm d s, \quad \forall t \in [0, 1]. $$

There exists a constant $C$ (depending on $\alpha, \beta$) such that $\sup_{t \in [0, 1]} f(t) \le C$.$$ f(t) \le \int_0^t (t-s)^{-\frac{1}{2}} [f(s) + |f(s)|^{\beta}] \, \mathrm d s, \quad \forall t \in [0, 1]. $$

Can we pick such constant $C$ such thatI would like to ask if $\alpha=0$ then $f=0$?

Thank you so much for your elaboration!

A tight Grönwall-type upper bound

Let $\alpha \in (0, \infty)$ and $\beta \in (0, 1]$. We assume $f : [0, 1] \to [0, \infty)$ is a measurable and bounded function such that $$ f(t) \le \alpha + \int_0^t (t-s)^{-\frac{1}{2}} [f(s) + |f(s)|^{\beta}] \, \mathrm d s, \quad \forall t \in [0, 1]. $$

There exists a constant $C$ (depending on $\alpha, \beta$) such that $\sup_{t \in [0, 1]} f(t) \le C$.

Can we pick such constant $C$ such that if $\alpha=0$ then $f=0$?

Thank you so much for your elaboration!

Does $f(t) \le \int_0^t (t-s)^{-\frac{1}{2}} [f(s) + |f(s)|^{\beta}] \, \mathrm d s$ imply $f=0$?

Let $\beta \in (0, 1)$. We assume $f : [0, 1] \to [0, \infty)$ is a measurable and bounded function such that $$ f(t) \le \int_0^t (t-s)^{-\frac{1}{2}} [f(s) + |f(s)|^{\beta}] \, \mathrm d s, \quad \forall t \in [0, 1]. $$

I would like to ask if $f=0$?

Thank you so much for your elaboration!

Source Link
Akira
  • 825
  • 2
  • 9
  • 16

A tight Grönwall-type upper bound

Let $\alpha \in (0, \infty)$ and $\beta \in (0, 1]$. We assume $f : [0, 1] \to [0, \infty)$ is a measurable and bounded function such that $$ f(t) \le \alpha + \int_0^t (t-s)^{-\frac{1}{2}} [f(s) + |f(s)|^{\beta}] \, \mathrm d s, \quad \forall t \in [0, 1]. $$

There exists a constant $C$ (depending on $\alpha, \beta$) such that $\sup_{t \in [0, 1]} f(t) \le C$.

Can we pick such constant $C$ such that if $\alpha=0$ then $f=0$?

Thank you so much for your elaboration!