Suppose that $f$ is a continuous function on $\mathbb{R}$. I want to estimate the definite integral $$ I:= \int_{0}^a [f(x)-f(0)]dx $$ by the upper bound $M = \sup_{x\in[0,a]}|f(x)|$ and the variation $V_f(x,\delta):=\sup_{y\in [x,x+\delta]}|f(x)-f(y)|$

I have a small $\delta>0$ and eventually make $\delta \rightarrow 0$. And fix a positive constant integer $k$. Then the part $$I_1:=\int_0^{k\delta} [f(x)-f(0)]dx$$ can be precisely estimated by $$ |I_1|\leq\delta \sum_{j=0}^{k-1} V_f(j\delta,\delta)$$ due to the continuity of $f$. Although we can also estimate it by upper bound $|I_1|\leq 2M \delta$, it is clearly not the best choice.

However, if I have a constant $0<c<a$ and don't do anything to it later, then the variation is not the best choice for the part $$ I_2 := \int_{c}^a [f(x)-f(0)]dx$$ because $x$ is far away from $0$. So, it may be the best choice to estimate by the upper bound. $$ I_2 \leq 2(a-c)M. $$

The question is what is the best estimation for the rest interval $$ I_3 := \int_{k\delta}^{c}[f(x)-f(0)] ?$$ It seems either the variation or the upper bound is not the best choice. That is, they both overestimate $|I_3|$. Of course, if $f$ satisfies some Holder continuity, $|I_3|$ can be estimated well. Here, nevertheless, I wonder what estimation we can do for the most general continuous functions.