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Neil Strickland
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Closed formula for Hermite polynomials

Hermite polynomials $H_k(x), x \in \mathbb{R}, k \in \mathbb{N}$ are defined by the formula $$ H_k(x)=(-1)^k e^{x^2} \frac{d^k}{d x^k}\left(e^{-x^2}\right) . $$ Each $H_k(x)$ is a polynomial of exact degree $k$. The Hermite polynomials are also given by the generating function $$ e^{2 x w-w^2}=\sum_{k=0}^{\infty} \frac{H_k(x)}{k !} w^k $$

Define the Hermite functions $\tilde{h}_k(x)$ by $$ \tilde{h}_k(x)=H_k(x) e^{-\frac{1}{2} x^2} . $$

We have the Mehler's formula, for the Hermite functions $\tilde{h}_k(x)$.

Proposition For $w \in \mathbb{C},|w|<1$ and $x, y \in \mathbb{R}$, $$\sum_{k=0}^{\infty} \frac{\tilde{h}_k(x) \tilde{h}_k(y)}{2^k k !} w^k=\left(1-w^2\right)^{-\frac{1}{2}} e^{-\frac{1}{2} \frac{1+w^2}{1-w^2}\left(x^2+y^2\right)+\frac{2 w}{1-w^2} x y}$$

One has $$\int_\Bbb R\left(\tilde{h}_k(x)\right)^2 d x=2^k k ! \sqrt{\pi} .$$

Thus we can normalise $\tilde{h}_k(x)$ by defining $$h_k(x)=\left(2^k k ! \sqrt{\pi}\right)^{-\frac{1}{2}} \tilde{h}_k(x)$$

This family $\{h_k(x): k \in \mathbb{N}\}$ is an orthonormal system in $L^2(\mathbb{R})$. But we can say more.

Theorem The system $\{h_k(x): k \in \mathbb{N}\}$ is an orthonormal basis for $L^2(\mathbb{R})$. Consequently, every $f \in L^2(\mathbb{R})$ has an expansion $$f(x)=\sum_{k=0}^{\infty}\left(f, h_k\right) h_k(x)$$ where the series converges to $f$ in the $L^2$ norm.

My question is there a close formula for this sum: $$\sum_{k=0}^{\infty}\frac{1}{k+a}h_k(x)h_k(y)$$