Say a non negative $r$ is a Galois radius of $n$ of type $(a,b)$ if $n-r=p^a$ and $n+r=q^b$ with $p$ and $q$ prime and positive $a$ and $b$. If $a\neq b$, say $r$ is "unbalanced" and say $s$ is an inversion shift of $r$ if either $r-s$ or $r+s$ is a Galois radius of $n$ of type $(b,a)$. Let $s_{0}(n,r)$ be the smallest positive inversion shift of $r$.
Does any unbalanced Galois radius of any large enough integer have an inversion shift? Does one have $s_{0}(n,r)\ll_{\varepsilon}r^{1+\varepsilon}$?
More precisely, is the following conjecture true?
Conjecture: for every couple of different positive integers $(a,b)$, there is an integer $N_{a,b}$ such that every integer $n$ greater than $N_{a,b}$ which has a Galois radius $r$ of type $(a,b)$ has a Galois radius $r'$ of type $(b,a)$.
Edit March 9th 2023: we may consider the special case where $a$ and $b$ have the same Hamming weight $H$ (as the number of $1$'s in the binary representation of an integer) and write them as a block of $0$'s and $1$'s of given length $L$. The set $\mathcal{P}_{L,H}$ of permutations of such integers forms a finite group $G_{L,H}$ under composition (if we also count balanced Galois radii hence allow $a=b$). Among its elements, those of order $2$ may correspond bijectively to the set of inversion shifts of Galois radii of type $(a,b)$ of a given set of integers $n$.
A particularly interesting subcase would be $L=2H$ and the involution we seek the flipping of each bit. That way we would have $a=(2^{L}-1)-b$ and the even more special subsubcase $L=2$ would be worth studying per se. Indeed in that case $G_{2,1}\cong C_{2}$, which may lead to the following conjecture:
Asymptotic Riemann-Hamming-Goldbach-Galois (RHG2 for short) conjecture
Assume RH. Then every large enough integer has a Galois radius of level at most 2.
We might be able to prove that in this case the level $l=ab$ of a primality radius corresponds to the cardinal of a subgroup of $C_{2}$ and that every large enough integer having a Galois radius of level $2$ has a Galois radius of level $1$ while the converse should not be true.