If $M_{g}$ is the moduli space of Riemann surfaces of genus $g$, and $M^1_{g}$ is the moduli space of Riemann surfacea of genus $g$ with one boundary, how can we show that the natural map:

$M^1_{g} \rightarrow M_{g}$

is a fibration (I think it is a fiber bundle), and the fiber over a point $S \in M_{g}$ is the sphere bundle associated to the tangent bundle of the Riemann surface $S$?

I don't have appropriate coordinates; that is probably why I can't show it.

I am asking this question because I want to show that if $M^{m,b}_{g,n}$ is the moduli space of Riemann surfaces of genus $g$ and $b$ boundary components, and with $n$ interior marked points, $m=(m_1,m_2,\ldots,m_{b})$ marked points on the boundary, $m_i$ marked points on the $i$th boundary component, then the homology dimension

$H_i(M^{m,b}_{g,n},Q)=0,$ for $i\ge 6g-7+2n+3b+m$ possibly excludes some bad low dimensional cases.

I learned one way is to assoicate it to the mapping class group (especially we have a virtual cohomological dimension of the mapping class group by Harer, "On virtual cohomological dimension of mapping class group of oriented surface") and the homology of mapping class group is the same as the homology of the above moduli space, but I still don't understand how it works. Thank you for help.