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Tried to finally clarify the question and mentioned known special case from earlier version/comments

When $\lambda$-commutativity implies commutativity?

Let $\mathcal{B}(F)$ the algebra of all bounded linear operators on an infinite-dimensional complex Hilbert $F$.

Let $T,S\in\mathcal{B}(F)$. The pair $(T,S)$ is said to $\lambda$-commute if there exists $\lambda\in \mathbb{C}^*$ such that $TS=\lambda ST$. I am looking for necessary and sufficient conditions on the operators $S$ and $T$ such that $(T,S)$ $\lambda$-commute, then they already commute.

I know already that $S,T \geq 0$ or $S,T \leq 0$ is a sufficient condition for $S$ and $T$ to commute if they $\lambda$-commute, but this is far from necessary.

Schüler
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