Let $P(s)$ be Prime zeta function.

Numerical evidence suggests these:

$$ \sum_{k=1}^\infty \frac{(-1)^{k}P(3k)}{k}=\log{(\frac{1}{945}\frac{\pi^6}{\zeta(3)})}\qquad (1)$$

$$ \sum_{k=1}^\infty \frac{(-1)^{k}P(nk)}{k}=\log{(\frac{1}{a(n)}\frac{\pi^{2n}}{\zeta(n)})}\qquad (2)$$

for natural $n$ and $a(n)$ is OEIS A002432 Denominators of zeta(2n)/Pi^(2n).

In $a(n)$ we have $\zeta(2n)$ and in (2) $\zeta(n)$.

Is (1) and/or (2) true?