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1 vote
3 answers
995 views

SO(3) knot polynomials

Can one use the real lie algebra so(3) to get knot polynomials? If so, do they have a skein relation (I presume they would, if they come from R-matrices in some standard way. If so, is the R-matrix ...
Sam Lewallen's user avatar
  • 1,129
18 votes
4 answers
2k views

Who thought that the Alexander polynomial was the only knot invariant of its kind?

I apologize that this is vague, but I'm trying to understand a little bit of the historical context in which the zoo of quantum invariants emerged. For some reason, I have in my head the folklore: ...
Sammy Black's user avatar
  • 1,756
7 votes
2 answers
497 views

Computations of the Link homology categorifying the second colored Jones polynomial

Has anybody done computations of such a theory? Is there a place I could look up and see what the answers are for low crossing knots?
Charlie Frohman's user avatar
8 votes
2 answers
834 views

What is the Alexander polynomial of a point?

According to the Baez-Dolan cobordism hypothesis, an extended TQFT is determined by its value on a single point. This value a fully dualizable object of a symmetric monoidal $n$ category (a fully ...
Daniel Moskovich's user avatar
19 votes
4 answers
2k views

What are the points of Spec(Vassiliev Invariants)?

Background Recall that a (oriented) knot is a smoothly embedded circle $S^1$ in $\mathbb R^3$, up to some natural equivalence relation (which is not quite trivial to write down). The collection of ...
Theo Johnson-Freyd's user avatar
28 votes
2 answers
3k views

Why is the Alexander polynomial a quantum invariant?

When we think of quantum invariants, we usually think of the Jones polynomial or of the coloured HOMFLYPT. But (arguably) the simplest example of a quantum invariant of a knot or link is its Alexander ...
Daniel Moskovich's user avatar

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