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1 vote
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Do almost all Gibbs' measures satisfy the weak-Poincare Inequality?

I am trying to interprete the discussion given in Section 3 of this paper, https://core.ac.uk/download/pdf/82217936.pdf Lets suppose we restrict to considering Gibbs's measures of the form $\sim e^{-...
Student's user avatar
  • 617
2 votes
0 answers
167 views

Convex ordering of measures that are obtained by different push-forwards of a same measure

Suppose that we have a probability measure $\rho$ which is supported on $\mathbb{R}^d$ and absolutely continuous w.r.t. the Lebesgue measure. Take two vector fields $F, G : \mathbb{R}^d \rightarrow \...
theouscidda6's user avatar
0 votes
1 answer
379 views

Concentration of norm of linearly transformed normal random vector as dimension go to infinity

Earlier asked on MSE, but didn't get an answer, so posting here: Let $X=(X_1 \dots X_n) \in \mathbb{R}^n, X_i\sim N(0,1), iid.$ Let $B: \mathbb{R}^n \to \mathbb{R}^n $ be the diagonal linear map: $...
Learning math's user avatar
-1 votes
1 answer
138 views

On the concentration of Lipschitz functions near its expectation, where the vector has identical but not independent, components

Consider the random vector $X:=(X_1\dots X_1) \in \mathbb{R}^n, X_1 \sim \mathcal{N}(0,1).$ Notice the identical components, they're identically distributed but not independent. Now, I was wondering ...
Learning math's user avatar
1 vote
1 answer
91 views

A distribution which is Wasserstein-close to a compactly supported distribution is almost compactly supported

I wonder whether this is true: If a distribution is very close (in the Wassertein sense) to another distribution with compact support, then the former must put only tiny amount of mass outside a ...
dohmatob's user avatar
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