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5 votes
1 answer
364 views

Groups with no proper non-trivial fully invariant subgroup

Let $G$ be a finite group. A subgroup $H$ of $G$ is said to be characteristic if $\phi(H)\subseteq H$, $\forall \phi \in \operatorname{Aut}(G)$ and fully invariant if $\phi(H)\subseteq H$, $\forall \...
Nick Belane's user avatar
1 vote
0 answers
125 views

Is the commutator of the holomorph of generalized quaternion group abelian?

Let $Q_{2^{n}} = \langle x, y \mathrel\vert x^{2^{n-1}}=y^4 = 1, x^{2^{n-2}}=y^2, y^{-1}xy = x^{-1} \rangle$ be the generalized quaternion group of order $2^{n}$. Let $\operatorname{Hol}(Q_{2^{n+1}})$ ...
bidermeyer's user avatar
1 vote
0 answers
80 views

Are these maps, associated to finite simple graphs, interesting?

Given a finite simple graph on $n$ vertices, say $G = (V,\, E)$, where $$ V = \{ v_1, \ldots , \, v_n \} $$ and $$ E \subseteq \{ (v_a, \, v_b) \, | \, 1 \leq a < b \leq n \},$$ does there exist a ...
Malkoun's user avatar
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9 votes
1 answer
420 views

Automorphisms and epimorphisms of finite groups

All groups in this question are finite, and epimorphism means surjective group homomorphism. Suppose I have two epimorphisms $f,g\colon G\to H$. This implies that $\ker(f)$ and $\ker(g)$ have the ...
Neil Strickland's user avatar
1 vote
1 answer
227 views

What happens when you internalize outer automorphisms?

Given a finitely presented group $G = (Gen|Rel)$, we have a set of inner automorphisms $\{ \phi_a(x) = axa^{-1} | a \in G\}$. Defining the set of outer automorphisms to be those automorphisms of $G$ ...
Samuel Schlesinger's user avatar