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6 votes
2 answers
217 views

A convolution-type identity for the "major index"

For a permutation $\pi\in\frak{S}_n$, define the number of descents of $\pi$ as $$\text{des}(\pi)=\vert\{i: \pi(i)>\pi(i+1)\}\vert.$$ The following is a well-known (and interesting) identity: $$\...
T. Amdeberhan's user avatar
5 votes
0 answers
350 views

Sum over permutations involving sign

The problem is to evaluate the following sum over all permutations $\sigma\in S_{d}$ of $\{1,2,...,d\}$: $\displaystyle\sum_{\sigma\in S_{d}}\text{sgn}(\sigma)\displaystyle\frac{1}{\prod_{i=1}^{d}(\...
Abhishek Halder's user avatar
4 votes
3 answers
509 views

How to calculate: $\sum\limits_{k=0}^{n-m} \frac{1}{n-k} {n-m \choose k}$

How to calculate: $$\sum _{k=0}^{n-m} \frac{1}{n-k} {n-m \choose k}.$$
luw's user avatar
  • 327
10 votes
2 answers
1k views

A cancellation property for permutations?

Let $S_n$ be the group of $n$-permutations. Denote the number of inversions of $\sigma\in S_n$ by $\ell(\sigma)$. QUESTION. Assume $n>2$. Does this cancellation property hold true? $$\sum_{\...
T. Amdeberhan's user avatar
28 votes
3 answers
3k views

Sum over permutations is 1

This might be easy, but let's see. Question 1. If $\mathfrak{S}_n$ is the group of permutations on $[n]$, then is the following true? $$\sum_{\pi\in\mathfrak{S}_n}\prod_{j=1}^n\frac{j}{\pi(1)+\pi(...
T. Amdeberhan's user avatar
5 votes
1 answer
2k views

Number of Permutations with k-inversions and with a single clamped value

This question is cross-posted from math.stackexchange because it might be too technical. Let $S_n$ be the symmetric group. Recall that the number of inversions of a permutation $\sigma\in S_n$ is the ...
Alex R.'s user avatar
  • 4,952