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5 votes
1 answer
278 views

Set-theoretic generation by circuit polynomials

Let $P$ be a prime ideal in $S=\mathbb{C}[x_1,\ldots , x_n],$ and write $[n] = \{ 1, \ldots , n \}.$ The algebraic matroid of $P$ can be defined according to circuit axioms as follows: $C\subset [n]$ ...
tim's user avatar
  • 396
4 votes
0 answers
101 views

A relation between $Spec((1+I)^{-1}R)$ and $Spec(R/J)$

Let $R$ be a commutative ring with identity and let $I$ and $J$ be two finitely generated ideals of $R$. Clearly $1+I:=\{1+i:i\in I\}$ is a multiplicative closed subset of $R$. We can consider the ...
Bruce's user avatar
  • 41
3 votes
0 answers
158 views

A characterization for a commutative ring with a special intersection property for prime ideals

Let $R$ be a commutative ring with $1$ with the property that for any infinite family $\{P_i\}_{i\in I}$ of distinct prime ideals of $R$ we have $\cap_{i\not= j} P_i\subseteq P_j$ for all but fnitely ...
A. C. Biller's user avatar
1 vote
0 answers
65 views

Non-minimal Krull associated primes of a PF-ring

A commutative ring $R$ is said to be a PF-ring if every principal ideal of $R$ is a flat $R$-module. Also, a prime ideal $P$ of $R$ to be a Krull associated prime of $R$ if for every element $x\in P$ ,...
user140640's user avatar
1 vote
0 answers
85 views

A special family of prime ideals

I am looking for a commutative ring $R$ with identity which has a family $F:=\{p_i\}_{i\in A}$ of prime ideals such that for each $n\in \mathbb{N}$ there exists $m\in \mathbb{N}$ with $n\leqslant m$ ...
Es.Ro's user avatar
  • 11
1 vote
0 answers
156 views

A family of maximal ideals

Let $m_i $, $i \in I,$ be an infinite family of maximal ideals in a commutative ring with identity (it is not supposed to be Noetherian). When does there exist $j \in I$ such that $\cap_{i\not= j} m_i\...
Alex's user avatar
  • 49
0 votes
0 answers
139 views

Primary ideals and radical of an ideal

Let $R$ be a regular local ring (for example, $R=\mathbb{C}\{x_1, \dots, x_n\}$) and let $\mathfrak{p}$ be a prime ideal in $R$. Given an ideal $\mathfrak{a} \subset R$ such that $\sqrt{\mathfrak{a}}=\...
Serge the Toaster's user avatar
0 votes
0 answers
251 views

"Strong Going-Down" Theorem

Let $\iota \colon A \subset B$ be a finite integral extension between domains. Suppose that $A$ is UFD, so $A$ is an integrally closed domain. $A$ and $B$ may not be noetherian ring. Choose a prime ...
Pierre MATSUMI's user avatar