Let G be the fundamental group of a compact 3-manifold which supports on its interior a complete non positively curved Riemannian metric and is a cilinder near de metric. Is G hyperbolic?
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1$\begingroup$ What is the last part of the first sentence supposed to say? At any rate, the fundamental group of a flat 3-torus is not hyperbolic. $\endgroup$– Autumn KentCommented Nov 17, 2011 at 14:01
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$\begingroup$ You are right, then change nonpositively by negatively $\endgroup$– Luis JorgeCommented Nov 17, 2011 at 14:24
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$\begingroup$ It is a standard result in Riemannian geometry that the fundamental group of a compact Riemannian manifold with strictly negative curvature has hyperbolic fundamental group since the universal cover is $CAT(k)$ for some $k < 0$. Does that answer your question, or are you asking about something else? $\endgroup$– Paul SiegelCommented Nov 17, 2011 at 14:32
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$\begingroup$ Actually I want to know if groups of that form (the way I difined in the first question) satisfy the k.theoretic farrell jones conjecture. I have another question. In the case of zero curvature what kind of groups may occur? $\endgroup$– Luis JorgeCommented Nov 17, 2011 at 14:43
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2$\begingroup$ If you only require a negatively curved metric on the interior then $G$ need not be hyperbolic. For example, the figure eight knot complement with the hyperbolic metric (a) has constant negative curvature and (b) is the interior of a compact three-manifold. But $G$ is not hyperbolic because the peripheral group is ${\mathbb{Z}}^2$. $\endgroup$– Sam NeadCommented Nov 17, 2011 at 18:11
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Yes, this follows from the geometrization theorem. A negatively curved complete manifold is atoroidal, and the manifold is irreducible, so there is a complete hyperbolic metric on the interior by geometrization.
In your comments, you ask about zero curvature. Then it is just a Euclidean manifold, with fundamental group a Bieberbach group.
answered Nov 17, 2011 at 16:58
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1$\begingroup$ I think he means word-hyperbolic (I didn't say the question made any sense...) $\endgroup$ Commented Nov 17, 2011 at 17:56
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1$\begingroup$ I see Igor - I always confuse 3-manifolds and their fundamental groups. $\endgroup$– Ian AgolCommented Nov 17, 2011 at 19:34