Timeline for Hyperbolicity of a fundamental group
Current License: CC BY-SA 3.0
7 events
when toggle format | what | by | license | comment | |
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Nov 17, 2011 at 18:11 | comment | added | Sam Nead | If you only require a negatively curved metric on the interior then $G$ need not be hyperbolic. For example, the figure eight knot complement with the hyperbolic metric (a) has constant negative curvature and (b) is the interior of a compact three-manifold. But $G$ is not hyperbolic because the peripheral group is ${\mathbb{Z}}^2$. | |
Nov 17, 2011 at 16:58 | answer | added | Ian Agol | timeline score: 3 | |
Nov 17, 2011 at 14:43 | comment | added | Luis Jorge | Actually I want to know if groups of that form (the way I difined in the first question) satisfy the k.theoretic farrell jones conjecture. I have another question. In the case of zero curvature what kind of groups may occur? | |
Nov 17, 2011 at 14:32 | comment | added | Paul Siegel | It is a standard result in Riemannian geometry that the fundamental group of a compact Riemannian manifold with strictly negative curvature has hyperbolic fundamental group since the universal cover is $CAT(k)$ for some $k < 0$. Does that answer your question, or are you asking about something else? | |
Nov 17, 2011 at 14:24 | comment | added | Luis Jorge | You are right, then change nonpositively by negatively | |
Nov 17, 2011 at 14:01 | comment | added | Autumn Kent | What is the last part of the first sentence supposed to say? At any rate, the fundamental group of a flat 3-torus is not hyperbolic. | |
Nov 17, 2011 at 13:54 | history | asked | Luis Jorge | CC BY-SA 3.0 |