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Let $m: \mathcal{L}(\mathbb{R}^{d \times d}) \to \mathbb{R}$ be the function

$$ m[H] = \frac{\lambda_{\max}(H[\mathbf{I}])}{\lambda_{\max}(H)}, $$

where $\lambda_{\max}$ denotes the largest eigenvalue.

Now let $Q: \mathbb{R}^{d \times d} \to \mathbb{R}^{d \times d}$ be a self-adjoint, completely positive linear map satisfying the following conditions:

  • $\sigma(Q) \subset [0, 1]$ (the spectrum of $Q$ is contained within $[0, 1]$),
  • $Q[\mathbf{I}] \preccurlyeq \mathbf{I}$ (the action of $Q$ on the identity matrix is dominated by the identity matrix in the Löwner order).

Question

What is the tightest possible upper bound on $m[Q^k - Q^{k+1}]$ for $k \in \mathbb{N}^+$?

The best bound I have derived so far is:

$$ m[Q^k - Q^{k+1}] \leq \min\left(\sqrt{d}, \frac{1}{1 - \|Q\|} m[Q^k]\right) \leq \min\left(\sqrt{d}, \frac{1}{\|Q\|^k - \|Q\|^{k+1}}\right), $$

where $\|Q\|$ is the operator norm of $Q$.

Additional Notes:

The $\sqrt{d}$ term arises from the relationship between the spectral norm and the Frobenius norm: for a $d \times d$ matrix $A$,

$$ \|A\| \leq \|A\|_F \leq \sqrt{d} \|A\|, $$

which bounds the maximal possible value of $m[H]$ based on $H[\mathbf{I}]$ and the spectrum of $H$.

Specific Interest

Can we improve this bound, particularly by further bounding $m[Q^k - Q^{k+1}]$ in terms of $m[Q^k]$ or $m[Q^{k+1}]$?

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