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Given the vorticity form of the Euler equations in $2D$ with stream function $\psi$

\begin{align} \omega_t + \nabla^\perp \psi \cdot \nabla\omega &= 0 \\ \Delta \psi = \omega \end{align}

we know that $v =: \nabla^\perp \psi$ with $\text{curl } v = \omega$ solves the classical Euler equations

\begin{align} v_t + (v \cdot \nabla) v &= -\nabla p \\ \text{div } v &= 0 \\ v(0, \cdot) = v_0 \end{align}

for some pressure term $p$.


Question: If instead we're given a perturbation of the vorticity-stream formulation such that $\Delta \psi = \omega + \varepsilon \phi$ --

Is there a clean way of showing that one can 'invert' the perturbed vorticity formulation to an Euler system with forcing term of the 'same size' as the perturbation?

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  • $\begingroup$ Could you perhaps briefly comment on the notation? $\nabla^\perp$ is the vector curl, and $\operatorname{curl}$ the scalar curl? If the stream function $\psi$ and $\omega$ are scalar and, what is then $\omega_t +\nabla^\perp\psi\cdot \omega$? $\endgroup$ Commented Nov 27 at 21:25
  • $\begingroup$ Thank you @BertoldoBaccalà -- there is a a typo in there, $\nabla^{\perp}$ is just the counter-clockwise rotated gradient by $\frac{\pi}{2}$. I missed the gradient on $\omega$. $\endgroup$
    – user43389
    Commented Nov 28 at 15:37

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