How did Ramanujan come up with the Ramanujan summation and is it possible to extend it to higher sets (Everything circled in red is what I'm interested in (+ the Cauchy integral to make it Dedekind completed) )
-
$\begingroup$ This post: terrytao.wordpress.com/2010/04/10/… explores what is meant by "divergent summation" including Ramanujan's work $\endgroup$– Sidharth GhoshalCommented Dec 4, 2023 at 15:05
-
2$\begingroup$ I admit that the question contains a "big picture". $\endgroup$– Jukka KohonenCommented Dec 4, 2023 at 16:13
1 Answer
Ramanujan's reasoning is analysed in detail by Berndt, in his discussion of chapter 6 of Ramanujan's notebooks. Ramanujan starts from the Euler-MacLaurin summation formula, $$\sum_{k=1}^x f(k)=C +\int_1^x f(t)\,dt+\tfrac{1}{2}f(x)+\sum_{k\geq 1}\frac{B_{2k}}{(2k)!}\frac{d^{2k-1}}{dx^{2k-1}}f(x),$$ and focuses on the constant $C$, which he uses to find the asymptotic expansion of $\sum_{k=1}^x f(k)$ as $x\rightarrow\infty$. This approach was made somewhat more rigorous by Hardy.
In this way Ramanujan obtained the notorious identities $\sum 1 =-\tfrac{1}{2}$ and $\sum k = -\tfrac{1}{12}$. For a $p$-adic interpretation of the latter sum, see this MO post.
-
1$\begingroup$ This answer is already more than the question deserves. $\endgroup$ Commented Dec 6, 2023 at 5:44