I have a function $\phi(x): \mathbb{R} \to [0, 2 \pi)$, which describes phase of another function $$f = e^{i \phi(x)}. $$
I am interested in the following problem. If I know the function/distribution $B(x): \mathbb{R} \to \mathbb{C}$ $$f(x) * f(-x)^* = \int_{-\infty}^{\infty} e^{i (\phi(\xi) - \phi(\xi-x))}d\xi = B(x)$$ can I recover $\phi(x)$?
My initial idea was to figure out the correspondence between $\phi(x)$ and $\hat{f}(k)$ since I know $\hat{f}(k) \hat{f}(k)^*$, where $$\hat{f}(k) = \int_{-\infty}^{\infty} f(x) e^{-2 \pi ikx} dx$$ but according to What are the properties of the fourier transform of a phase-only function? $\hat{f}(k)$ is a pretty hard to characterize distribution. This is also related to When I know self convolution of the complex function can I recover function itself or its modulus?, where I got negative answer for more general problem. Physical reasoning of this is to recover the intensity of the pure phase object from Fresnel integral, see Wikipedia knowing $I_z(x,y) = E(x,y,z)E(x,y,z)^*$ how to recover $I_0(x,y) = E(x,y,0)E(x,y,0)^*$ in the special case of $E(x,y,0) = e^{i\psi(x,y)}$. There is some theory that relies upon the linearization of exponential function but I am interested if I can do something without it.