Let $G =$ PGL$_{n}(\textbf{C})$ and $T$ be the image in $G$ of the subgroup of the invertible diagonal matrices of $\operatorname{GL}_{n}(\textbf{C})$. Let $A$ and $B$ be two elementary abelian $2$-subgroups in $T$ of the same rank.
The Kronecker product $\otimes I_{2}$ embeds $A$ and $B$ in $H$ = $\operatorname{PGL}_{2n}(\textbf{C})$. If $A$ and $B$ are not conjugate in $G$, will $A\otimes I_{2}$ and $B\otimes I_{2}$ not be conjugate in $H$? Intuitively, they are not conjugate in $H$ but I'm not sure of tools to tackle it. Maybe subgroup conjugacy is an equivalent relation and $\otimes I_{2}$ reserves it?
Edit: Some thinking made based on the input in the comment. If $A$ and $B$ are not conjugate in $G$, and we assume $A\otimes I_{2}$ and $B\otimes I_{2}$ are conjugate, attempt to get a contradiction. Since $A\otimes I_{2}$ and $B\otimes I_{2}$ are both block diagonal matrices with blocks $I_{2}$ and $-I_{2}$, if there always exists a "block permutation matrix" with each block $I_{2}$, then we're done. But I'm not sure about the existence of such a "block permutation matrix"... Any hints would be appreciated.