The condition for a connected $(q+1)$-regular graph to be Ramanujan is that every nonzero eigenvalue $\lambda$ of the graph Laplacian satisfy $$q+1-2\sqrt{q}\le \lambda\le q+1+2\sqrt{q}.$$ With a little bit of manipulation, we can rewrite this condition as the polynomial inequality $$\lambda^{2}+q^{2}-2\lambda q-2\lambda-2q+1\ \le0$$ which surprisingly is symmetric in $\lambda$ and $q$, despite the completely different role played by $q$ and $\lambda$ here.
This might just be a coincidence, but I think it's surprising enough to ponder whether there's anything more going on that would give a conceptual reason for this symmetry.