Let $(M^3,g)$ be a complete Riemannian manifold. Fix a two-sided immersion $\varphi : \Sigma^2 \to M$ from a closed surface into $M$, with unit normal $N$. Given $f \in C^\infty(\Sigma)$ and $\alpha : (-\varepsilon, \varepsilon) \to \mathbb{R}$ of sufficiently small $C^0$-norm, define $\varphi_t : \Sigma \to M$, for each $t \in (-\varepsilon, \varepsilon)$, by
$$ \varphi_t(x) = \exp_{\varphi(x)}(\alpha(t) f(x) N(x)), \quad x \in \Sigma, t \in (-\varepsilon, \varepsilon), $$
where $\exp$ is the exponential map of $(M,g)$.
Is there a reasonable formula for the area of the Riemannian surface $(\Sigma, \varphi_t^\ast g)$? For fixed $f$ satisfying $\int_{\Sigma} f H_{\Sigma} \, \mathrm{d}A = 0$ (here $H_\Sigma$ is the mean curvature of $\varphi$), is it possible to choose $\alpha$ of the form $\alpha(t) = t \beta(t)$ so that this area is constant with respect to $t$?