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Bäcklund transformations may be used also in ODE to solve non-linear problems; for instance, it's well known that for the equation

$$ \frac{\mathrm{d}^2\omega}{\mathrm{d}t^2}=\sin\omega \tag{*}\label{star} $$

we can define the transformation

$$ \frac{\mathrm{d}\omega}{\mathrm{d}t}-i\frac{\mathrm{d}\tau}{\mathrm{d}t}=2e^{i\lambda}\sin\left(\frac{\omega+i\tau}{2} \right), $$

with $\tau(t)$ satisfying

$$ \frac{\mathrm{d}^2\tau}{\mathrm{d}t^2}=\sinh\tau, $$

and then (for any $\lambda$) with some choice of $\tau$ ($\tau=0$ in particular) we may find a solution for $\omega$. This works relatively easy because the equation \eqref{star} is an autonomous equation, i.e., it does not contain the independent variable explicitly. On the other hand, if we consider

$$ \frac{\mathrm{d}^2\omega}{\mathrm{d}t^2}=t\cdot\sin\omega \tag{**}\label{starstar} $$

(or equations with any "forcing" $f(t)$ other that $f(t)=t$) the equation is no longer autonomous and it's not at all evident how to construct a Bäcklund transformation analogous to that of \eqref{star}. (I'm assuming this method may help to solve the equation, which appears when considering some problems of deformations of elastic membranes.) The question is then how to construct a transformation that may help to solve \eqref{starstar} analytically in terms of $\omega(t_0)$ and $\omega'(t_0)$, with $t_0$ some fixed real.

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  • $\begingroup$ Mathematica cannot solve it, so it seems unlikely there is a closed form solution. Without the factor t, why do you need Bäcklund transformation? Why not just multiply both sides by $\omega'$ and integrate? $\endgroup$ Commented Feb 10, 2022 at 23:20

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