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Closely related, but different from this solved quesion

Let $\zeta^{(k)}(s)$ denote the $k$-th derivative of Riemann zeta function. For real $x$, let $[x]$ denote the nearest integer to $x$.

Conjecture 1: For integer $B \ge 2$ we have $[\zeta^{(1)}(1-1/B)]=[\zeta^{(1)}(1+1/B)]$

Conjecture 2: Let $k=1$ or $k=2$. Then $[\zeta^{(k)}(1-1/B)]= -B^{k+1}\cdot k!$

According to computations with mpmath and pari/gp, both hold up to 10^5 for integer $B$.

From the linked question, $k=41$ violates generalization of (2).

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  • $\begingroup$ good old $41$ ... $\endgroup$ Commented Oct 4, 2021 at 17:16
  • $\begingroup$ @PietroMajer I don't get your comment. 41 is not counterexample according to my computations. $\endgroup$
    – joro
    Commented Oct 4, 2021 at 17:33
  • $\begingroup$ $41$ is also the first positive integer number $n$ that violates "$n^2+n+41$ is prime" :) $\endgroup$ Commented Oct 4, 2021 at 17:55
  • $\begingroup$ (I think both conjectures are true; it's just a matter of bounding a remainder in the Laurent expansion of $\zeta$ at $1$) $\endgroup$ Commented Oct 4, 2021 at 17:57

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