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David Mumford gives in his book Algebraic Geometry I, Complex Projective Varieties on page 61 a definition of Chow's Lemma which has at least for me not a usual form:

If says that a closed $^*$-analytic subset $X \subset \mathbb{P}_{\mathbb{C}}^n$ is a finite union of algebraic varieties.

On 'closed $^*$-analytic subset': on page 61 Mumford defined a locally closed subset $X \subset \mathbb{C}^n$ as follows. Let $U \subset \mathbb{C}^n$ open set and $X \subset U$ closed in $U$. Then $X$ is $^*$-analytic if $X$ can be decomposed as

$$X = X^{(r)} \cup X^{(r-1)} \cup ... \cup X^{(0)} $$

where for all $i$, $ X^{(i)}$ is a $i$-dimensional complex submanifold of $U$ and the closure $\overline{X^{(i)}} \subset X^{(i)} \subset X^{(i-1)} \subset ... \subset X^{(0)}$.

Now in modern literature the Chow's Lemma is known as (this one is from Wikipedia but quoted from Grothendieck's EGA II):

If $X$ is a scheme that is proper over a noetherian base $ S $, then there exists a projective $S$ -scheme $ X' $ and a surjective $S$-morphism $ f:X'\to X $ that induces an isomorphism $ f^{{-1}}(U)\simeq U$ for some dense $U\subseteq X$.

Question: is there any relation between Mumford's version and Wikipedia version. Remark: the wikipedia version is exactly that one from EGA II.

My conjecture: if $S= \operatorname{Spec} (\mathbb{C})$, ie $X$ is a complex scheme or say for sake of simplicity a variety, are these two statements equivalent? For example I don't know but probably the wikipedia version could be proved by applying Mumford's version which allows using analytic methods.

But that's only a conjecture of mine, nothing more. Does anybody know more on this issue?

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    $\begingroup$ Same Chow, different lemma. $\endgroup$ Commented Dec 26, 2020 at 19:22
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    $\begingroup$ Actually Mumford's book discusses the Chow theorem, which as Donu says has nothing to do with Chow's lemma. $\endgroup$
    – abx
    Commented Dec 26, 2020 at 19:27
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    $\begingroup$ Decades ago that version in Mumford was known as Chow's Lemma, and the EGA II version had not yet achieved the same prominence, etc. $\endgroup$ Commented Dec 26, 2020 at 19:54
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    $\begingroup$ see section I.10 of Mumford's redbook for the classic version of the wikipedia Chow lemma. $\endgroup$
    – roy smith
    Commented Dec 27, 2020 at 0:00
  • $\begingroup$ Perhaps my earlier comment was a bit cryptic, but other people have clarified it. Let me add that Chow's name is attached to several different things in algebraic geometry. See en.wikipedia.org/wiki/Wei-Liang_Chow $\endgroup$ Commented Dec 27, 2020 at 15:32

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