The periodization operator $\mathrm{Per}$ is defined for a Schwartz function $\varphi \in \mathcal{S}(\mathbb{R})$ as \begin{equation} \mathrm{Per} \{ \varphi \} (x) = \sum_{n \in \mathbb{Z}} \varphi( x - n ), \quad \forall x \in \mathbb{R}. \tag{1} \end{equation} The sum in (1) is of course well-defined pointwise due to the rapid decay of $\varphi$ and we then have that $\mathrm{Per}\{\varphi\}$ is an infinitely smooth $1$-periodic function. More generally, it is possible to define the periodization operator $\mathrm{Per}$ over rapidly decaying distributions $\mathcal{O}_{C}'(\mathbb{R})$ (see for instance this paper for details). We then have \begin{equation} \mathrm{Per} : \mathcal{O}_{C}'(\mathbb{R}) \rightarrow \mathcal{S}'(\mathbb{T}) \tag{2} \end{equation} continuously, the latter space being the space of $1$-periodic distributions.
Question: Can we define a proper subspace of $\mathcal{S}(\mathbb{R})$ that maximally extends the periodization in a precise sense? That is, a space on which the periodization is well-defined, with a natural topology that makes the periodization continuous, with good reasons for its "maximality"?