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All schemes will be of finite type over a field $k$. Say I have a closed embedding $\iota: X \hookrightarrow Y$ of smooth $S$-schemes for some scheme $S$ (in particular it is a regular embedding). Then locally on $X$ and $Y$ we have factorizations

$X \overset{f}{\rightarrow} S \times \mathbb{A}^n \rightarrow S$

$Y \overset{g}{\rightarrow} S \times \mathbb{A}^m \rightarrow S$

where $f$ and $g$ are etale. My question is whether it is always possible to get a local factorization of $\iota $ as

$\require{AMScd}$ \begin{CD} X @>{\iota}>> Y\\ @VVV @VVV \\ S \times \mathbb{A}^n @>{\iota'}>> S \times \mathbb{A}^m \end{CD}

where $\iota'$ is defined by $ x_{n+1}= \dots x_{m} = 0$? Moreover, if this is possible can we set things up so that the diagram is cartesian?

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    $\begingroup$ It seems this is possible Zariski-locally on $Y$, see SGA 1, Exp. II, Proposition 4.9 (the equivalence of (i) and (iv)). $\endgroup$ Commented Jul 31, 2019 at 16:35
  • $\begingroup$ Thanks @MinseonShin this was very helpful. $\endgroup$
    – Anette
    Commented Aug 2, 2019 at 15:12

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