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Let $k$ be an algebraically closed field, let $d\ge 2$ be an integer and let $f,g\in k[x,y,z]$ be two homogeneous polynomials of degree $d$ without common factor.

We want to know what are the singularities of the curve $C_{[\lambda:\mu]}$ given by $\lambda f+\mu g=0$, for a general $[\lambda:\mu]\in \mathbb{P}^1$. If a point $p\in\mathbb{P}^2$ is a singular point of the curves $C_{[1:0]}$ and $C_{[0:1]}$ given by $f=0$ and $g=0$ then it is of course singular for each $C_{[\lambda:\mu]}$. If $\mathrm{char}(k)=0$, then by Bertini there are no other singularities. If $\mathrm{char}(k)=p>0$, it is false: take for instance $f=x^p$ and $g=y^p$. Are all counterexamples of this type ? One can of course replace $p$ by a power of $p$ and maybe do some more general examples. For instance, if $d<2p$, is the case $f=x^p$ and $g=y^p$ the only possibility (up to change of coordinates)?

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    $\begingroup$ You are asking about "generic smoothness / Sard's Lemma" for the morphism from $\mathbb{P}^2 \setminus \text{Zero}(f,g)$ to $\mathbb{P}^1$ given by $[x,y,z] \mapsto [f(x,y,z),g(x,y,z)]$. There are many other ways that generic smoothness fails beyond "inseparable morphisms" such as $[x^p,y^p]$. One example that often arises is "quasi-elliptic fibrations": $f(x,y,z) = x^2z^{p-2} + (y-x)^p$, $g(x,y,z) = x^2z^{p-2} + (y-z)^p$. For $[s,t]\neq [1,1]$, the singularities of $s^p f - t^p g$ are $[x,y,z] = [0,t,t-s]$ and $[x,y,z]=[s-t,s,0]$. $\endgroup$ Commented Jun 18, 2019 at 11:05
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    $\begingroup$ There is also an example in Hartshorne (Ch III Ex. 10.7) which seems relevant. $\endgroup$
    – meh
    Commented Jun 18, 2019 at 16:00

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I am just writing an answer summarizing the counterexamples from the comments and adding one positive result for small degree.

Let $k$ be an algebraically closed field. Let $X$ and $Y$ be quasi-projective, connected, smooth $k$-schemes. Let $f:X\to Y$ be a flat $k$-morphism.

Problem. Is $f$ smooth over a dense open subset of $Y$?

By Generic Smoothness / Sard's Lemma, this is true if $\text{char}(k)$ equals $0$. However, if $\text{char}(k)=p$ is positive, this can fail. As the OP explains, the induced map of function fields might be inseparable, in which case $f$ is nowhere smooth. However, there are other examples, such as the ones from the comments. In particular, for $$\mathbb{P}^1_k=\text{Proj}\ k[\lambda,\mu],\ \ \mathbb{P}^2_k = \text{Proj}\ k[x,y,z],$$ $$f = x^dz^{p-d} + (y-x)^p, \ \ g = x^dz^{p-d} + (y-z)^p, \ \ 1\leq d \leq p-1,$$ $$Y=\mathbb{P}^1_k \setminus\{[1,1]\}, \ \ U = \mathbb{P}^2_k \setminus\{[1,0,1]\},$$ $$ X\subset Y\times_{\text{Spec}\ k} U, \ \ X =\text{Zero}(\lambda f - \mu g),$$ the projection $f$ from $X$ to $Y$ is a flat, surjective morphism of quasi-projective, connected, smooth $k$-schemes that is smooth on a dense open of $X$, yet the singular locus of $f$ surjects to $Y$.

There is a positive result. Let $Y$ be a quasi-projective, connected, smooth $k$-scheme. Let $X$ be a locally closed subscheme of $Y\times_{\text{Spec}\ k} \mathbb{P}^N_k$ that is connected and smooth. Assume that the projection $f$ from $X$ to $Y$ is flat. Denote the dimension of the generic fiber of $f$ by $n$. Denote the projective degree of the (closure) of the generic fiber by $e$. In the PhD thesis of Jan Gutt, there is the following result.

Jan Gutt
Hwang-Mok rigidity of cominuscule homogeneous varieties in positive characteristic
https://arxiv.org/pdf/1305.5296.pdf

Lemma 4.2.5 If the singular locus of the generic fiber of $f$ has dimension $d$, then the projective degree of the associated $d$-cycle is $\leq e(e-1)^{n-d}$. In particular, if $p> e(e-1)^n$, then the generic fiber of $f$ is smooth.

I recall that Will Sawin showed me examples demonstrating the sharpness of the inequality. If Will wants to add those examples, that would be great. Otherwise, I will try to add those myself in a few days.

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