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Let $(M,\mathcal B, \mu)$ be a probability space which $M=\{A_{1},A_{2},...,A_{N}\}^{\mathbb{N}}$ ($A_{i} \in GL(d ,\mathbb{R})$) and $\mu=p^{\mathbb{N}}$. Let $F:M\times \mathbb R^d\to M\times \mathbb R^d$ be a linear cocycle, i.e. $F(x,v):=(\sigma(x),A(x)v)$, defined by a measurable function $A:M\to GL(d)$ over a one side shift $f:M\to M$ that preserves $\mu.$

A measure $\eta$ on $\mathbb{PR^{d}}$ is called stationary measure of linear cocycle if $\eta=\sum p_{i} A_{i_{*}} \eta$.

Question

Could someone give two example such that in first example we have a unique stationary measure and another example we have two stationary measure?

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  • $\begingroup$ Sure: let $A_1$ be the lower triangular matrix with 1’s on the diagonal and below; and $A_2=A_1^T$. Let $B_1$ and $B_2$ be any diagonal matrices. Then $A_1,A_2$ have a unique stationary measure (this is the typical case), while $B_1,B_2$ have stationary measures in the coordinate directions. $\endgroup$ Commented Oct 22, 2018 at 2:28
  • $\begingroup$ @AnthonyQuas Thanks a lot. Let X is x axis and Y is y axis. Is $\eta=p_{1} \delta_{X}+p_{2}\delta_{Y} $ Stationary measure $A_{1} , A_{2}$ ?and $\eta_{1}=(p_{1}+p_{2})\delta_{X} ,\eta_{2}=(p_{1}+p_{2})\delta_{Y}$ of $B_{1},B_{2}$. $\endgroup$
    – Michal
    Commented Oct 22, 2018 at 20:19
  • $\begingroup$ The stationary measures for the B process are delta_X and delta_Y. The stationary measure for the A process is fully supported on $\mathbb{PR}^2$. $\endgroup$ Commented Oct 24, 2018 at 1:50

1 Answer 1

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If $A_1=\begin{pmatrix}1&0\\1&1\end{pmatrix}$ and $A_2=\begin{pmatrix}1&1\\0&1\end{pmatrix}$, and the measure on $\{A_1,A_2\}^{\mathbb Z}$ is the $(\frac 12,\frac 12)$ Bernoulli measure, then there is a unique stationary measure: given a sequence of 1's and 2's indexed by $\mathbb Z^-$, $\ldots,\omega_{-3},\omega_{-2},\omega_{-1}$, define $x_\omega$ to be the point of $\mathbb{PR}^2$ in the direction $\lim_{n\to\infty}A_{\omega_{-1}}\ldots A_{\omega_{-n}}\begin{pmatrix}1\\1\end{pmatrix}$. (The limit exists since the $A$'s are contracting on the positive cone). The unique stationary measure is $\int \delta_{x_\omega}\,d\mathbb P(\omega)$, where $\mathbb P$ is the Bernoulli measure on $\{1,2\}^{\mathbb Z^-}$. It's not hard to check from the definition that it is stationary. It's also quite easy to check from the above that any measure on the non-negative cone is attracted to this measure. A bit more work is needed to deal with measures with support off the non-negative cone, but one can convince oneself that the mass is gradually attracted to the non-negative cone.

The second example is the easy one: if $B_1$ and $B_2$ are any invertible diagonal matrices, then it is immediate to check that $\delta_X$ and $\delta_Y$, the measures supported on the $X$ and $Y$ direction are stationary.

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