Too long for a comment. The math experiment done with Maple 2018
restart; [seq(seq(seq(int(hypergeom([m-n, m+n+1], [m+1], z)*hypergeom([m-k+1, m+k+2], [m+2], z), z = 0 .. 1), m = 1 .. max(k-1, n)), n = 1 .. 5), k = 1 .. 5)]
performs
$$ [\int_{0}^{1}\!{\mbox{$_2$F$_1$}(1,4;\,3;\,z)}\,{\rm d}z,-\infty ,
\int_{0}^{1}\!{\mbox{$_2$F$_1$}(2,5;\,4;\,z)}\,{\rm d}z,\infty ,-
\infty ,\infty ,-\infty ,\infty ,-\infty ,\infty ,\infty ,-\infty ,
\infty ,-\infty ,\infty ,1,0,\int_{0}^{1}\!
{\mbox{$_2$F$_1$}(1,6;\,4;\,z)}\,{\rm d}z,1/6,-\infty ,\infty ,0,
\infty ,-\infty ,\infty ,1/15,-\infty ,\infty ,-\infty ,\infty ,0,
\int_{0}^{1}\!{\mbox{$_2$F$_1$}(1,4;\,3;\,z)}\,{\rm d}z,1/3,1,1/10-1/
10\, \left( {\mbox{$_2$F$_1$}(-2,5;\,2;\,1)} \right) ^{2},0,\int_{0}^{
1}\!{\mbox{$_2$F$_1$}(1,8;\,5;\,z)}\,{\rm d}z,1/10,2/9,-\infty ,
\infty ,0,0,\infty ,-\infty ,\infty ,2/9,-\infty ,\int_{0}^{1}\!
{\mbox{$_2$F$_1$}(2,5;\,4;\,z)}\,{\rm d}z,0,0,\int_{0}^{1}\!
{\mbox{$_2$F$_1$}(1,6;\,4;\,z)}\,{\rm d}z,1/6,1/3,1,1/18-1/18\,
\left( {\mbox{$_2$F$_1$}(-3,6;\,2;\,1)} \right) ^{2},{\frac{3}{28}}-{
\frac {3\, \left( {\mbox{$_2$F$_1$}(-2,7;\,3;\,1)} \right) ^{2}}{28}},0
,\int_{0}^{1}\!{\mbox{$_2$F$_1$}(1,10;\,6;\,z)}\,{\rm d}z,1/15,2/15,1/
4,-\infty ,\infty ,0,\infty ,-\infty ,\infty ,2/15,1/4,-\infty ,
\infty ,0,0,0,\int_{0}^{1}\!{\mbox{$_2$F$_1$}(1,8;\,5;\,z)}\,{\rm d}z,
1/10,{\frac{31}{180}},1/3,1,1/28-1/28\, \left(
{\mbox{$_2$F$_1$}(-4,7;\,2;\,1)} \right) ^{2},1/16-1/16\, \left(
{\mbox{$_2$F$_1$}(-3,8;\,3;\,1)} \right) ^{2},1/9-1/9\, \left(
{\mbox{$_2$F$_1$}(-2,9;\,4;\,1)} \right) ^{2},0,\int_{0}^{1}\!
{\mbox{$_2$F$_1$}(1,12;\,7;\,z)}\,{\rm d}z]
$$