3
$\begingroup$

I'm wondering if the following statement is true: Let $A$ be a $C^*$-algebra and $\phi: A\rightarrow A$ be a $*$-homomorphism. Is there always an element $a\in A$ such that the map

$\left\{ \phi^{n}:=\phi \circ ...\circ \phi \mid n\in\mathbb{N}\right\} \rightarrow A$, $\phi^n\mapsto \phi^{n}\left(a\right)$

is injective?

$\endgroup$
0

1 Answer 1

10
$\begingroup$

In any Banach space $B$, if $S$ is a countable set of bounded linear maps, there is $a \in B$ such that $S\ni T \mapsto Ta \in B$ is injective. This follows easily from the Baire Category Theorem: $B$ is not the union of the countably many closed, nowhere dense sets $\{x \in B \mid T_i x = T_j x\}$.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .