4
$\begingroup$

I just stumbled on a set of prime-generating polynomials of the form $$9 n^2-3 H n+H (H+1)/4$$ (where $H$ is a Heegner number $>11$), which generate the same number of distinct primes as their more familiar counterparts. There is some overlap in the primes generated by $n^2 - n + 41$ and $9 n^2-489 n+6683$ for example, but they are not all the same.

Are these of any interest, and are there other prime-generating polynomials that are related directly to the Heegner numbers? Also, why are the coefficients $9$ and $3$ involved?

$\endgroup$

2 Answers 2

5
$\begingroup$

According to Wikipedia, Rabinowitz showed that $n^2 + n + p$ is prime for $n=0, \ldots, p-2$ iff $p = (1+H)/4$, $H$ a Heegner number. If you substitute $n = 3 m - (H+1)/2$, you get your polynomial $9 m^2 - 3 H m + H(H+1)/4$.

$\endgroup$
1
  • $\begingroup$ true, but if I substitute $n$ for anything other than $3 m - (H+1)/2$, I don't get all prime values for $m=0 \ldots p-2$. Why these values in particular? $\endgroup$
    – martin
    Feb 2, 2016 at 6:26
0
$\begingroup$

There is a way to generate an infinite number of prime generating polynomials with of course a fluctuating number of primes that was posted in the math stackexchange few months back.

$\endgroup$
3

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.