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I asked a similar question on math stack exchange but didn't get an answer so I will try to ask it here. Any help/suggestion is most than welcome! Let $D$ be a linear differential operator with polynomial coefficients on $\mathbb{R}^n$. Thus

$$\displaystyle D=\sum_{\lvert \alpha\rvert\leqslant k} P_\alpha(x) \frac{\partial^{\lvert \alpha\rvert}}{\partial x^\alpha}$$

where the $P_\alpha$'s are polynomial functions on $\mathbb{R}^n$. Consider $D$ as an endomorphism of the space of Schwartz functions $\mathcal{S}(\mathbb{R}^n)$. My question is now the following:

Is the image of $D$ a closed subspace of $\mathcal{S}(\mathbb{R}^n)$ (for its natural Frechet topology)? Is there any good reason for that? Even an answer in the particular case $n=1$ would be greatly appreciated!

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    $\begingroup$ This seems to be a difficult question. You certainly know the Lojasiewicz-Hörmander theorem that multiplication with a polynomial (or analytic function) defines a closed range operator. This is already very deep. For constant coefficient differential operators you can use Fourier transformation but the general case seems to be far out of reach. $\endgroup$
    – Jochen Wengenroth
    Nov 6, 2015 at 8:11

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