1
$\begingroup$

Is there any (simple) approximation of this Hypergeometric function: $ _2F_1((b-1)a,b;ba;x) $, where $0<x<1$ and $b>a>1$.

Thanks!

Improve this question
$\endgroup$
2
  • $\begingroup$ Other than the Maclaurin polynomials? $\endgroup$
    – Robert Israel
    Commented Mar 19, 2015 at 23:32
  • $\begingroup$ @RobertIsrael Yes, if possible.. Note that I can accept the following assumption: $x\ll1$ $\endgroup$
    – tam
    Commented Mar 21, 2015 at 11:27

1 Answer 1

Reset to default
0
$\begingroup$

There are Pade approximations. See these slides by Matala-aho. I believe the results in the classical case you are asking about are due to Grisha Chudnovsky (1979, cited in the slides).

Improve this answer
$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .