Find the following limits:
(1) $\limsup_{n\to\infty } \sin (n!) $
(2) $\liminf_{n\to\infty } \sin (n!) $
(3) $\limsup_{n\to\infty } \cos (n!) $
(4) $\liminf_{n\to\infty } \cos (n!) .$
Find the following limits:
(1) $\limsup_{n\to\infty } \sin (n!) $
(2) $\liminf_{n\to\infty } \sin (n!) $
(3) $\limsup_{n\to\infty } \cos (n!) $
(4) $\liminf_{n\to\infty } \cos (n!) .$
My guess is that the lim infs are $-1$ and the lim sups are $+1$, but I think this requires better information about rational approximations of $\pi$ than we have available. What I can say, though, is that $\lim_{n \to \infty} \sin(n! \pi e) = 0$, while $\lim_{n \to \infty} \cos((2n)! \pi e) = -1$ and $\lim_{n \to \infty} \cos((2n+1)! \pi e) = +1$.
Now we strongly suspect, but haven't been able to prove, that $\pi e$ is irrational. If by some miracle it happens to be rational, then the limit points of $\exp(n! i)$ as $n \to \infty$ are a finite set of roots of unity.