Do quotients of amenable groups C*-algebras satisfy the UCT?

Let G be a discrete amenable group.

General Question: Let $J$ be an ideal of $C^*(G)$, the group C*-algebra of $G.$ Does $C^*(G)/J$ satisfy the universal coefficient theorem (UCT)?

I am mainly interested in the following special case:

Specific Question: Same as the above question, but suppose moreover that G is finitely generated, nilpotent and $J$ is the kernel of an irreducible representation.

I know embarrassingly little about the UCT. I'm aware of Tu's 1999 paper "La conjecture de Baum-Connes pour les feuilletages moyennables" from which (I'm told) it follows that amenable groupoid C*-algebras satisfy the UCT, the various constructions that preserve the UCT ($\mathbb{Z}$-actions, inductive limits, two out of three property), and little else.

EDIT: Elizabeth Gillaspy and I recently showed the answer to the specific question is "yes" arXiv:1510.05469 [math.OA]. I still don't have any idea for the general case.

• Did you ever find an answer to this question? – Yemon Choi May 18 '15 at 20:25
• @YemonChoi No, I just found several "I'm sure that's true"s from experts – Caleb Eckhardt May 19 '15 at 12:49
• This might be a difficult question because even taking $J$ to be trivial the question is whether the rather arbitrary amenable $C^*$-Algebra $C^*(G)$ satisfies UCT. But it is unsettled if every amenable (separable) $C^*$-Algebra is in the boot strap class. – hänsel Mar 20 '16 at 22:23
• @hansel The case you mention was settled by Tu in the paper I quoted in the original post. – Caleb Eckhardt Mar 27 '16 at 3:45
• @hansel Quotients of amenable C*-algebras are amenable. – Caleb Eckhardt Mar 30 '16 at 14:10