Let $A$ and $B$ be $W^{*}$-algebras, let $X$ be an $A-B$-equivalence bimodule (according to the definition given in "Morita equivalence for $C^*$-algebras and $W^*$-algebras" by Rieffel, link:http://dmitripavlov.org/scans/rieffel.pdf ), the **conjugate equivalence bimodule** of $X$, written $\widetilde{X}$, is the space $X$ but with conjugate operations of $A, B$ and the complex numbers, that is,

$b\widetilde{x} = \widetilde{xb^*}$, $\widetilde{x}a = \widetilde{a^*x}$,

and with inner products

$\langle \widetilde{x},\widetilde{y} \rangle_B = \langle x,y \rangle_B$, etc.

for $x,y \in X, b \in B, a \in A$.

Rieffel says that this $\widetilde{X}$ is a $B-A$-equivalence bimodule, the proof is apparently verified by routine computations, thing is, I was curious about this:

**If $\widetilde{X}$ is a $B-A$-equivalence bimodule, shouldn't $\langle -,- \rangle_B: \widetilde{X} \times \widetilde{X} \rightarrow B$ satisfy**

**$ \langle b\widetilde{x},\widetilde{y} \rangle_B = b \langle \widetilde{x},\widetilde{y} \rangle_B$**

**or something similar to condition (3) of definition 3.1 on page 63 in Rieffel's paper?**

(which says that $\langle -,- \rangle_B: X \times X \rightarrow B$ should satisfy

$\langle x,yb \rangle_B = \langle x,y \rangle_Bb$

for all $x,y \in B$, $b \in B$).

Thanks :)