3
$\begingroup$

Suppose $X$ is a finite subset of the plane and for $0\leq \theta<\pi$, let $l_\theta$ denote the line through the origin having angle $\theta$ with the positive $x$-axis. For how many values of $\theta$ can the projection $P_{l_\theta}$ of $X$ onto $l_\theta$ have smaller order of magnitude? Say $|P_{l_\theta}(X)|\ll|X|^{1-\epsilon}$? For almost all $\theta$ this should not happen. Can it happen for more than a bounded number of $\theta$?

$\endgroup$

1 Answer 1

6
$\begingroup$

Yes; indeed the number of such $\theta$ can grow as $|X|^{1-2\epsilon}$, which is unbounded for all $\epsilon < 1/2$. For large $N$ let $X$ be the set of integer points $(x,y)$ with $x^2 + y^2 < N$, so $|X| \sim \pi N$. If $l_\theta$ has rational slope $a/b$ then $P_{l_\theta}(x,y)$ depends only on the integer $bx+ay$, which has absolute value at most $\sqrt{a^2+b^2} \cdot N^{1/2}$ by Cauchy-Schwarz. Therefore $|P_{l_\theta}(X)| \ll \sqrt{a^2+b^2} \cdot N^{1/2}$. This is $\ll |X|^{1-\epsilon}$ if $a^2+b^2 \ll X^{1-2\epsilon}$, and the number of such $\theta$ grows as $X^{1-2\epsilon}$, QED.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .