It is well known that in the case of integer order differentiation the formula $\partial_{x}f(x,u(x))=\partial_{u}f\cdot \partial_{x}u+\partial_{x}f\cdot u$ holds. If we define fractional derivative via Fourier transform F as $D_{x}^{\alpha}u(x)=F^{1}[{(i\xi)^{\alpha}\widehat{u}(\xi)}]$, where ^ denotes the Fourier transform, is there a similarly formula for $D_{x}^{\alpha}f(x,u(x))$?
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$\begingroup$ The fractional derivative is of order 0<\alpha<1 $\endgroup$ – Milos Sep 19 '13 at 8:06

1$\begingroup$ dx.doi.org/10.1137/0501026 $\endgroup$ – Carlo Beenakker Sep 19 '13 at 20:44
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If you are interested in estimates (rather than pointwise equalities), you might check out this paper of Christ and Weinstein:
http://deepblue.lib.umich.edu/bitstream/handle/2027.42/29171/0000217.pdf?sequence=1
See in particular Proposition 3.1 therein.