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Q: How do you solve 5x plus 1 equals 20?

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5x + 2 = 22 5x = 22 - 2 5x = 20 5x/5 = 20/5 x=4

If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept

y=5x+2 if y equals -4

x = -1.2, y = -3

If: 5x+1 = 21 Then: 5x = 21-1 => 5x = 20 Divide both sides by 5 and so x = 4

you cant

23

3

7

x = -8

-5x + 30 = 20 -5x + 30 - 30 = 20 - 30 -5x = -10 -5x / -5 = -10 / -5 x = 2

5x + 20 = 4x +30 5x - 4x = 30 - 20 x = 10

x=35

5x + 4y = 204y = -5x + 20y = (-5/4)x + 5

172=x

Then x = 6 Therefore; 5x + 3 = 33 First you have to solve the value of X: 8X + 5X + 2X +4X = 114; OR 19x = 114. When you divide both sides of the equation by 19 to solve for X, you find that X = 6. Ergo, 5X + 3 = 30 + 3 = 33; hence, 5X + 3 = 33.

Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.

(x-3)(x-2)

x=8

-5x+50 = 25 -5x = 25-50 -5x = -25 x = 5

2x + x + 4 +2x = x + 20 5x + 4 = x + 20 5x - x = 20 - 4 4x = 16 x = 4

sin7x-sin6x+sin5x

5x+y=-7 3x+y=15 8=D

33

To solve for two unknowns (x and y) it is necessary to have two independent equations.

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