But don't assume knowledge of any topological dimension theory. Here is a specific approach (an open problem):

Does there exist a separable metric space $X$ such that the following two conditions hold:

- $|X|\ge 2$;
- for every closed $A\subseteq X$ such that $X\setminus A$ is disconnected, there exists $Y\subseteq A$ homeomorphic to $X$;

**?**

(I formulated this question around 1960, perhaps without ever publishing it; I didn't work on it--too bad, since I like this question :-) )

BTW, you're welcome to use any means (including the dimension theory) to construct $X$. If you did it without using dimension theory or fpp for $I^n$ then you'd obtain a new proof of $\dim I^n\ge n$ and of *fpp* for $I^n$, for every $n$ (it's well known and easy that if this *fpp* holds for every natural $n$, then for arbitrary cardinal $n$ too).

**TERMINOLOGY:** *fpp* = Fixed Point Property.

fpp? ${}$ $\endgroup$ – Mariano Suárez-Álvarez Feb 16 '13 at 6:30