Let $X$ be a 2-dimensional CW complex and let $c\subset X$ be a 2-cell attached along a simple closed loop $\gamma$ in the 1-skeleton $X^{(1)}$. For a natural number $n\ge 2$ consider the operation of $n$-rewinding $c$, which means to replace $c$ by a new 2-cell $c^n$ whose boundary is attached to $X^{(1)}$ along $\gamma^n=\gamma\circ\dotsb\circ\gamma$, the $n$-fold concatenation of $\gamma$ with itself. In other words, while $c$ winds around $\gamma$ once, $c^n$ winds around $\gamma$ $n$ times.
Question: Suppose that $X$ does not embed in $\Bbb R^4$. Let $X^n$ be obtained from $X$ by $n$-rewinding a 2-cell $c$ for some $n\ge 2$. Is it possible that $X^n$ now does embed in $\Bbb R^4$? Or does rewinding always preserve non-embeddability?
If there is a general answer to this question that would be highly interesting, but I would also be satisfied with an answer to the following special case: $X=\mathcal K_7^2$, the full 2-complex on $K_7$, obtained from the complete graph $K_7$ by attaching a 2-cell along each triangle. This complex does not embed in $\Bbb R^4$, but it becomes embeddable if a single 2-cell is deleted (see this answer to "Almost embedding" the complete 2-dimensional complex $\mathcal K_7^2$ into $\Bbb R^4$). I wonder whether the same result can be achieved by rewinding a 2-cell.