3
$\begingroup$

I am reading Luca Capogna's article An Embedding theorem and the Harnack inequalitiy for nonlinear subelliptic equations. In this article, the authors proved the following theorem

(Theorem 2.3) Let $U\subset \mathbb{R}^n$ be a bounded open set and denote by $Q$ the homogeneous dimension relative to $U$. Let $1<p<Q$. Then there exist $C>0$ and $R_{0}>0$ such that for any $x\in U$, $B_{R}=B(x,R)$ ($B_{R}$ is the subunit ball) with $R\leq R_{0}$, we have $$ \left(\frac{1}{|B_{R}|}\int_{B_{R}}|u|^{sp}dx \right)^{\frac{1}{sp}}\leq CR\left(\frac{1}{|B_{R}|}\int_{B_{R}}|D_{L}u|^{p}dx\right)^{\frac{1}{p}}$$ for any $u\in S_{0}^{1,p}(B_{R})$, Here, $1\leq s\leq \frac{Q}{Q-p}$.

The author says that a standard partition of the unity argument implies $$ S_{0}^{1,p}(U)\hookrightarrow L^{q}(U)$$ for any $U\subset\subset \mathbb{R}^n$. I don't know how to use the partition of unity to obtain this claim. Can someone show it in detail?. Furthermore, can we deduce the following fact ? $$ \left(\int_{U}|u|^{q}dx\right)^{\frac{1}{q}}\leq C\left(\int_{U}|D_{L}u|^{p}dx \right)^{\frac{1}{p}},$$ for $U\subset\subset \mathbb{R}^n$ instead the subunit ball $B_{R}$?

My approach: since $\overline{U}$ is a compact set, then there exist $n$ subunit ball $B_{i}(x_{i},r_{i}) (i=1,\ldots,n)$ which cover $\overline{U}$ (We can assume that each $r_{i}\leq R_{0}$). Then there exists a partition of unity of $B_{i}(x_{i},r_{i}) (i=1,\ldots,n)$ satisfy

(1)$0\leq \phi_{i}\leq 1, \text{supp}\phi_{i}\subset B_{i}(x_{i},r_{i}) $ and $\phi_{i}\in C_{0}^{\infty}(\mathbb{R}^n)$.

(2) $$ \sum_{i=1}^{n}\phi_{i}=1 \qquad \forall x\in U $$

Then for a function $f\in S_{0}^{1,p}(U)$, we have $$ f=\sum_{i=1}^{n}f\phi_{i} $$ \begin{align*} \|f\|_{L^{q}(U)}&=\|\sum_{i=1}^{n}\phi_{i}f\|_{L^{q}(U)}\\ &\leq \sum_{i=1}^{n}\|\phi_{i}f\|_{L^{q}(U)}\\ &=\sum_{i=1}^{n}\|\phi_{i}f\|_{L^{q}(B_{i}(x_{i},r_{i}))}\\ &\leq \sum_{i=1}^{n} \|D_{L}(\phi_{i}f)\|_{L^{p}(B_{i}(x_{i},r_{i}))} \end{align*} I don't know if $$\sum_{i=1}^{n} \|D_{L}(\phi_{i}f)\|_{L^{p}(B_{i}(x_{i},r_{i}))}\leq C\|D_{L}f\|_{L^p(U)}$$ holds or not. Then I stuck here and don't know how to continue, Can some one help me? thank you very much!

$\endgroup$
12
  • 1
    $\begingroup$ This should be migrated to math.stackexchange.com. But the idea is to use a partition of unity subordinate to a locally finite covering of $U$ by open balls to write $u$ as a sum of functions, each compactly supported on one of the balls, and apply Theorem 2.3 to each of these functions. $\endgroup$
    – Deane Yang
    Commented Oct 17, 2016 at 0:32
  • $\begingroup$ @DeaneYang: You have enough reputation to vote to migrate... $\endgroup$ Commented Oct 17, 2016 at 2:38
  • 1
    $\begingroup$ Nate, thanks. Didn't know I had such powers. $\endgroup$
    – Deane Yang
    Commented Oct 17, 2016 at 3:45
  • 1
    $\begingroup$ It seems we can only obtain $$\|f\|_{L^{q}(U)}\leq C( \|D_{L}f\|_{L^{p}(U)}+\|f\|_{L^{p}(U)} )$$ will the sharp estimate $\endgroup$
    – pxchg1200
    Commented Apr 3, 2017 at 15:09
  • 1
    $\begingroup$ I have to concede that I appear to be wrong about this. I thought I knew how to do this, but I currently don't see how. If there is a global Poincaré inequality ($\|f\|_p \le C\|D_Lf\|_p$), then you would get the inequality. $\endgroup$
    – Deane Yang
    Commented Apr 6, 2017 at 3:05

1 Answer 1

2
+100
$\begingroup$

Disclaimer: Not an expert in analysis/PDE, happen to know tangential results while studying Whitney-type embeddings.

$S_{0}^{1,p}(U)\hookrightarrow L^{q}(U)$ for any $U\subset\subset \mathbb{R}^n$. I don't know how to use the partition of unity to obtain this claim.

There is a more general proof for Thm 2.3 in [1], shown in details by the same authors in a later paper [2].

Theorem 2.3 in [1] is the same as Theorem 1.2 in [2] with different notations. And the partition of unity should follow the same lines in the proof of Theorem 1.3 of [2]. The proof in details you asked for is in Sec 4 of [2].

In [2] they proved the theorem as a special case of Theorem 1.1 of [2], and in the process of proving Theorem 1.1 of [2], they also proved (Theorem 1.3 in [2]) the sub-elliptic inequality $$\left|\left\{ x\in B_{R}:\left|u(x)\right|>\lambda\right\} \right|^{\frac{Q-1}{Q}}\leq C_{3}\frac{1}{\lambda}E|B_{R}|^{\frac{-1}{Q}}\int_{B_{R}}|D_{X}u|dx$$ for some constant $C_3$. So the roadmap is $Thm1.3\rightarrow Thm1.4\text{(isoperimetric)}\rightarrow Thm1.1\rightarrow Thm1.2\text{(special case,=Thm2.3 in [1])}$. The partition of unity occurs in the proof of Thm 1.3 $$I_{\alpha}^{1}f(x)=\int_{B(x,\epsilon)}|f(\xi)|\frac{d(x,\xi)^{\alpha}}{|B(x,d(x,\xi))|}d\xi$$ $$I_{\alpha}^{2}f(x)=\int_{B(x,\epsilon)^{C}\cap B_{R}}|f(\xi)|\frac{d(x,\xi)^{\alpha}}{|B(x,d(x,\xi))|}d\xi$$ and then in the proof of Thm2.1 of [2], the author argued that both $I_\alpha$ can be bounded from above. This is formally a partition of unity, but its spirit is more like Calderon-Zygmund type argument. $$I_{\alpha}^{1}f(x)\leq C_{4}Mf(x)\epsilon^{\alpha}$$ where $M$ is the Hardy-Littlewood maximal operator over $B(x,r),r>0$, $$I_{\alpha}^{2}f(x)\leq C_{5}R^{Q}|B_{R}|^{-1}\epsilon^{\alpha-Q}\left\Vert f\right\Vert _{L^{1}(B_{R})}$$ with $C_4,C_5$ being constants. Let $I_\alpha=I_\alpha^1+I_\alpha^2$, then let $\alpha=1$ we reach Thm 1.3 and hence Thm 1.4 hence Thm 1.1. As a corollary we get Thm 1.2(Your Thm2.3).The details in proving the bound of $I_\alpha$'s are extremely obscure(for me), so please do read [2] for details.

Reference

[1]Capogna, Luca, Donatella Danielli, and Nicola Garofalo. "An embedding theorem and the Harnack inequality for nonlinear subelliptic equations." Communications in Partial Differential Equations 18.9-10 (1993): 1765-1794.

[2]Capogna, Luca, Donatella Danielli, and Nicola Garofalo. "The geometric Sobolev embedding for vector fields and the isoperimetric inequality." Comm. Anal. Geom 2.2 (1994): 203-215.

$\endgroup$
2
  • $\begingroup$ I can't find Theorem 1.2 in [2], I think your reference of [2] should be [2] Capogna L, Danielli D, Garofalo N. The geometric Sobolev embedding for vector fields and the isoperimetric inequality[J]. Comm. Anal. Geom, 1994, 2(2): 203-215. I am very appreciate for your answer, however, By the partition of unity, it seems we can only obtain $$\|f\|_{L^{q}(U)}\leq C( \|D_{L}f\|_{L^{p}(U)}+\|f\|_{L^{p}(U)} )$$ for $f\in S_{0}^{1,p}(U)$. it seems we need a poincare inequality to obtain $$\|f\|_{L^{q}(U)}\leq C( \|D_{L}f\|_{L^{p}(U)}) $$ for $f\in S_{0}^{1,p}(U)$ $\endgroup$
    – pxchg1200
    Commented Apr 10, 2017 at 2:17
  • $\begingroup$ intlpress.com/site/pub/files/_fulltext/journals/cag/1994/0002/… Yes you are right, correct the cite. I do not understand what you commented above, but it seems to me that [2] is an more precise version. Let me know why [2] cannot lead to [1]. @pxchg1200 $\endgroup$
    – Henry.L
    Commented Apr 10, 2017 at 12:23

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .