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There is a well-known theorem that between any two absolutely continuous Borel probability measures $\mu$ and $\nu$ on $\mathbb{R}^n$ there is an increasing triangular transformation $T : \mathbb{R}^n \to \mathbb{R}^n$, such that $\nu = T_∗\mu$ (see, for example, “Triangular transformations of measures” by Bogachev, Kolesnikov, and Medvedev).

There is another version of this theorem for smooth manifolds (non-compact Moser theorem). If $M$ is a noncompact connected oriented manifold and if $\mu$ and $\nu$ are volume forms on M with $\int_M \mu = \int_M \nu \le \infty$ and if each end of the manifold $M$ has finite $\mu$ volume if it has finite $\nu$ volume and infinite $\mu$ volume if it has infinite $\nu$ volume, then there is a diffeomorphism $\phi: M \to M$, such that $\phi^* \mu = \nu$. (See "Diffeomorphisms and volume-preserving embeddings for noncompact manifolds" by Greene and Shiohama.)

I am curious about the equivariant analog of either of these results.

More precisely, assume that a (compact?) group $G$ acts on $\mathbb{R}^n$ and $\mu$ and $\nu$ are two $G$-invariant (smooth) densities. Does there always exist a $G$-equivariant diffeomorphism $T : \mathbb{R}^n \to \mathbb{R}^n$, such that $\nu = T_∗\mu$?

Could you point out if this result is proved somewhere in the literature? Does the group $G$ have to be compact for it to hold?

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  • $\begingroup$ I added links to the papers, but there are two papers called "Triangular transformations of measures" by the same authors. I can't read Russian, so am not sure how they're related. I hope the link I gave was to the right one. $\endgroup$
    – LSpice
    Commented Aug 16, 2021 at 21:16
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    $\begingroup$ Are you assuming anything about the way in which $G$ acts on $\mathbb R^n$? $\endgroup$ Commented Aug 16, 2021 at 21:37
  • $\begingroup$ @AnthonyQuas I don't have a specific assumption on the action and I am more or less okay with any non-restrictive assumptions. However, the action should not be free. As an application in mind, I have a Euclidean group acting on $\mathbb{R}^n$. $\endgroup$
    – ivan
    Commented Aug 17, 2021 at 1:00

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