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Theo Johnson-Freyd
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can Can $(loglog\log\log m)/(loglog\log\log n)$ be rational?

Hi if m, nIf $m, n$ are two different positive integers, is it true that the ratio of the loglog of this two number always$\displaystyle \frac{\log\log m}{\log\log n}$ is necessarily irrational or not? log here is By $\log$ I mean the logarithm in base e not 10$e$ (not base $10$). I guess it is irrational, but I don't know why?

thanks

can (loglog m)/(loglog n) be rational?

Hi if m, n are two different positive integers, is it true that the ratio of the loglog of this two number always is irrational or not? log here is the logarithm in base e not 10. I guess it is irrational, but I don't know why?

thanks

Can $(\log\log m)/(\log\log n)$ be rational?

If $m, n$ are two different positive integers, is it true that the ratio $\displaystyle \frac{\log\log m}{\log\log n}$ is necessarily irrational? By $\log$ I mean the logarithm in base $e$ (not base $10$). I guess it is irrational, but I don't know why?

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asd
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Hi if m, n are two different positive integers, is it true that the ratio of the loglog of this two number always is irrational or not? log here is the logarithm in base e not 10. I guess it is irrational, but I don't know why?

thanks

Hi if m, n are two different positive integers, is it true that the ratio of the loglog of this two number always is irrational or not? I guess it is irrational, but I don't know why?

thanks

Hi if m, n are two different positive integers, is it true that the ratio of the loglog of this two number always is irrational or not? log here is the logarithm in base e not 10. I guess it is irrational, but I don't know why?

thanks

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asd
  • 47
  • 2

can (loglog m)/(loglog n) be rational?

Hi if m, n are two different positive integers, is it true that the ratio of the loglog of this two number always is irrational or not? I guess it is irrational, but I don't know why?

thanks