Background: Let $G$ be a complex reductive group, $T$ a maximal torus, $N$ the normalizer of $T$ in $G$, and $W = N/T$ the Weyl group. All in all, we have a group extension $$ 1 \to T \to N \to W \to 1 $$ of a finite group by a torus. Say $N$ "splits" if this extension splits, that is, if $W$ lifts to a subgroup of $N$.
It is well known that $N$ splits when $G=\text{GL}_n$: here $T$ is the diagonal matrices, $N$ is the group of monomial matrices, and a splitting is given by the permutation matrices. On the other hand, it is not true for every $G$ that the torus normalizer splits, the simplest example being $\text{SL}_n$ ($n\geq2$), where one cannot use the permutation matrices because the odd ones have determinant $-1$. It's a fun exercise to work out the other classical groups.
The group $N$ comes up all over in Lie theory and it was first studied, as far as I know, by Tits in a 1966 paper (zbmath)(zbmath). More recently, Moshe Adrian (zbmath)(zbmath) has completely answered the question of when $N$ splits, for $G$ almost simple. In particular:
Theorem: If $G$ is almost simple and exceptional then $N$ splits if and only if $G$ is of type $G_2$.
This result is already suggested (and maybe even directly implied) by work of Gal't in exceptional finite reductive groups (mathscinet, in Russian)(mathscinet, in Russian). I'm interested in the "exceptional" case of $G_2$, where $W$ is the dihedral group of order $12$.
Question: For the group $G_2$, is there a "simple" or "conceptual" explanation why the torus normalizer splits?
For example, $G_2$ is the automorphism group of the octonions $\mathbb O$ and one should be able to describe everything in these terms. Already the book of Springer and Veldkamp (zbmath)(zbmath) describes $T$ (Lemma 2.3.1) as automorphisms of $\mathbb O$ and my hope is that someone on this site who has drunk deep from the spring of the octonions can also describe $N$ and the splitting.
Alternatively, Tits's group for $G_2$ is of order $48$ and one should be able to recognize it as a semidirect product, though the computations involved intimidate me.