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simplified formulation (non-perfect implies positive char)
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YCor
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There is Is there a non-perfect field of positive characteristic not perfect in which polynomials, for a given of large degree, are reducible?

It is well-known that, in a real closed-closed field $K$, every polynomial of degree>2degree $>2$ is reducible in $K$. But in this case the characteristic of $K$ is zero.

My question is: there exists a non-perfect field $F$ of characteristic $p>0$ not perfect and a positive integer $n=n(F)$ such that all polynomials of degree  $>n$ are reducible in $F$.

Edit: polynomials of degree prime$>n$ coprime with the characteristic $p$$p>0$ of $F$

There is a field of positive characteristic not perfect in which polynomials, for a given degree, are reducible

It is well-known that, in a real closed field $K$, every polynomial of degree>2 is reducible in $K$. But in this case the characteristic of $K$ is zero.

My question is: there exists a field $F$ of characteristic $p>0$ not perfect and a positive integer $n=n(F)$ such that all polynomials of degree$>n$ are reducible in $F$.

Edit: polynomials of degree prime with $p$

Is there a non-perfect field in which polynomials of large degree are reducible?

It is well-known that, in a real-closed field $K$, every polynomial of degree $>2$ is reducible in $K$. But in this case the characteristic of $K$ is zero.

My question is: there exists a non-perfect field $F$ and a positive integer $n=n(F)$ such that all polynomials of degree  $>n$ are reducible in $F$.

Edit: polynomials of degree $>n$ coprime with the characteristic $p>0$ of $F$

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Medo
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It is well-known that, in a real closed field $K$, every polynomial of degree>2 is reducible in $K$. But in this case the characteristic of $K$ is zero.

My question is: there exists a field $F$ of characteristic $p>0$ not perfect and a positive integer $n=n(F)$ such that all polynomials of degree$>n$ are reducible in $F$.

Edit: polynomials of degree prime with $p$

It is well-known that, in a real closed field $K$, every polynomial of degree>2 is reducible in $K$. But in this case the characteristic of $K$ is zero.

My question is: there exists a field $F$ of characteristic $p>0$ not perfect and a positive integer $n=n(F)$ such that all polynomials of degree$>n$ are reducible in $F$.

It is well-known that, in a real closed field $K$, every polynomial of degree>2 is reducible in $K$. But in this case the characteristic of $K$ is zero.

My question is: there exists a field $F$ of characteristic $p>0$ not perfect and a positive integer $n=n(F)$ such that all polynomials of degree$>n$ are reducible in $F$.

Edit: polynomials of degree prime with $p$

deleted 2 characters in body
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Medo
  • 41
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It is well-known that, in a real closed field $K$, every polynomial of degree>2 is reducible in $K$. But in this case the characteristic of $K$ is zero.

My question is: there exists a field $F$ of characteristic $p>0$ not perfect and a positive integer $n=n(F)$ such that all polynomials of degree$>n$ are irreduciblereducible in $F$.

It is well-known that, in a real closed field $K$, every polynomial of degree>2 is reducible in $K$. But in this case the characteristic of $K$ is zero.

My question is: there exists a field $F$ of characteristic $p>0$ not perfect and a positive integer $n=n(F)$ such that all polynomials of degree$>n$ are irreducible in $F$.

It is well-known that, in a real closed field $K$, every polynomial of degree>2 is reducible in $K$. But in this case the characteristic of $K$ is zero.

My question is: there exists a field $F$ of characteristic $p>0$ not perfect and a positive integer $n=n(F)$ such that all polynomials of degree$>n$ are reducible in $F$.

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Medo
  • 41
  • 4
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