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Let $X$ be a positive integer number then. Then $\pi{(X+\ln^2{X})}-\pi{(X-\ln^2{X})}>\ln{X}$?

  • The prime-counting function is the function counting the number of prime numbers less than or equal to some real number $x$, It. It is denoted by $\pi{(x)}$. Using my computer I found that: Let $X$ befor any positive integer number $\leq 10^{9}$ then$X\leq 10^{9}$, $$\pi{(X+\ln^2{X})}-\pi{(X-\ln^2{X})}>\ln{X}$$

  • Question: IsDoes the result about hold? If for all positive integers $X$ be any positive integer number.?

Let $X$ be positive integer number then $\pi{(X+\ln^2{X})}-\pi{(X-\ln^2{X})}>\ln{X}$

  • The prime-counting function is the function counting the number of prime numbers less than or equal to some real number $x$, It is denoted by $\pi{(x)}$. Using my computer I found that: Let $X$ be positive integer number $\leq 10^{9}$ then $$\pi{(X+\ln^2{X})}-\pi{(X-\ln^2{X})}>\ln{X}$$

  • Question: Is the result about hold? If $X$ be any positive integer number.

Let $X$ be a positive integer. Then $\pi{(X+\ln^2{X})}-\pi{(X-\ln^2{X})}>\ln{X}$?

  • The prime-counting function is the function counting the number of prime numbers less than or equal to some real number $x$. It is denoted by $\pi{(x)}$. Using my computer I found that for any positive integer $X\leq 10^{9}$, $$\pi{(X+\ln^2{X})}-\pi{(X-\ln^2{X})}>\ln{X}$$

  • Question: Does the result hold for all positive integers $X$?

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Let $X$ be positive integer number then $\pi{(X+\ln^2{X})}-\pi{(X-\ln^2{X})}>\ln{X}$

  • The prime-counting function is the function counting the number of prime numbers less than or equal to some real number $x$, It is denoted by $\pi{(x)}$. Using my computer I found that: Let $X$ be positive integer number $\leq 10^{9}$ then $$\pi{(X+\ln^2{X})}-\pi{(X-\ln^2{X})}>\ln{X}$$

  • Question: Is the result about hold? If $X$ be any positive integer number.